What are the x-intercept and the y-intercept of the graph of $y = - \frac{1}{2} x - 5$ $y=-1/2x-5$ ?

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Answer 1 · 2016-12-15T15:49:24

The y-intercept is $- 5$ $-5$ or $(0, - 5)$ $(0, -5)$

The x-intercept is $- 10$ $-10$ or $(- 10, 0)$ $(-10, 0)$

Because this equation is in slope-intercept form:

$y = m x + c$ $y = mx + c$ where $m$ $m$ is the slope and $c$ $c$ is the y-intercept of $(0, c)$ $(0, c)$ .

So for this problem the y-intercept is $- 5$ $-5$ or $(0, - 5)$ $(0, -5)$

To find the x-intercept we need to set $y$ $y$ to $0$ $0$ and solve for $x$ $x$ :

$0 = - \frac{1}{2} x - 5$ $0 = -1/2x - 5$

$0 + 5 = - \frac{1}{2} x - 5 + 5$ $0 + 5 = -1/2x - 5 + 5$

$5 = - \frac{1}{2} x - 0$ $5 = -1/2x - 0$

$5 = - \frac{1}{2} x$ $5 = -1/2x$

$5 \times - 2 = - \frac{1}{2} x \times - 2$ $5 xx -2 = -1/2x xx -2$

$- 10 = \frac{- 2}{- 2} x$ $-10 = (-2)/(-2)x$

$- 10 = 1 x$ $-10 = 1x$

$- 10 = x$ $-10 = x$

What are the x-intercept and the y-intercept of the graph of y=−12x−5y=-1/2x-5?