What are the x intercepts for #f(x) = -2x^2 + 4x + 3#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Nghi N. · John D. May 22, 2015 f(x) = -2x^2 + 4x + 3 = 0 #D = d^2 = b^2 - 4ac = 16 + 24 = 40 = 4(10) -> d = +- 2sqrt10# Two x-intercepts: #x = -b/2a +- d/2a # #x = 1 + (2sqrt10)/-4 = 1 - (sqrt10)/2# #x = 1 + (sqrt10)/2# Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1390 views around the world You can reuse this answer Creative Commons License