What are three consecutive number whose sum is 111?

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Answer 1 · 2016-06-18T20:24:03

36, 37, and 38.

$36 + 37 + 38 = 111$ $36+37+38=111$

36, 37, and 38 are three consecutive numbers and their sum is 111.

Answer 2 · 2016-06-18T20:42:04

The three numbers are $36, 37, 38$ $36,37,38$ .

One number is $n$ $n$ , the consecutive is $n + 1$ $n+1$ and the following one is $n + 2$ $n+2$ . Then you are asking

$n + (n + 1) + (n + 2) = 111$ $n+(n+1)+(n+2)=111$

$3 n + 3 = 111$ $3n+3=111$

$3 n = 108$ $3n=108$

$n = \frac{108}{3} = 36$ $n=108/3=36$

so the first number is $36$ $36$ , the second is $37$ $37$ and the third is $38$ $38$ .