What are x and y if $10 x + 6 y = 0$ $10x+6y=0$ and $- 7 x + 2 y = 31$ $-7x+2y=31$ ?

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Answer 1 · 2018-05-09T04:42:58

$x = - 3, y = 5$ $color(crimson)(x = -3, y = 5$

$10 x + 6 y = 0, Eqn (1)$ $10 x + 6 y = 0, " Eqn (1)"$

$- 7 x + 2 y = 31, Eqn (2)$ $-7x + 2y = 31, " Eqn (2)"$

$21 x - 6 y = - 93, Eqn (3) = -3 * Eqn (2)$ $21x - 6y = -93, color(maroon)(" Eqn (3) = -3 * Eqn (2)"$

Adding Eqns (1), (3),

$31 x = - 93$ $31x = -93$

$x = - 3$ $color(crimson)(x = -3$

Substituting value of x in Eqn (2),

$21 + 2 y = 31$ $21 +2y = 31$

$2 y = 31 - 21 = 10, y = 5$ $2y = 31-21 = 10, color(crimson)(y = 5$

What are x and y if 10x+6y=010x+6y=0 and −7x+2y=31-7x+2y=31?