What can you say about a function f defined on #RR#, periodic and growing ?

1 Answer
Mar 19, 2018

There is no such function.

Explanation:

Function #f# cannot be periodic and everywhere increasing.

If #f# is periodic, then for some #p > 0#, we have #f(x+p) = f(x)# for all #x#. But this implies that #f# is not strictly increasing on #[x,x+p]#