What coefficient would the $O_{2}$ $O_2$ have after balancing $C_{4} H_{8} + O_{2} \to C O_{2} + H_{2} O$ $C_4H_8 + O_2 -> CO_2 + H_2O$ ?

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What coefficient would the $O_{2}$ $O_2$ have after balancing $C_{4} H_{8} + O_{2} \to C O_{2} + H_{2} O$ $C_4H_8 + O_2 -> CO_2 + H_2O$ ?

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Answer 1 · 2016-03-06T14:58:21

the coefficient is 6

Explanation:

The balancement of the reaction requires the conservation of mass, each atom of carbon in $C_{4} H_{8}$ $C_4H_8$ consumes one $O_{2}$ $O_2$ molecule, and every two atoms of hydrogen one oxygen atom is consumed.
So 4 molecules of $O_{2}$ $O_2$ used by carbon add to 2 molecules of $O_{2}$ $O_2$ used by hydrogen, in total 6 molecules of $O_{2}$ $O_2$
The balanced equation is:
$C_{4} H_{8} + 6 O_{2} \to 4 C O_{2} + 4 H_{2} O$ $C_4H_8 + 6 O_2 rarr 4CO_2 + 4H_2O$

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What coefficient would the $O_{2}$ $O_2$ have after balancing $C_{4} H_{8} + O_{2} \to C O_{2} + H_{2} O$ $C_4H_8 + O_2 -> CO_2 + H_2O$ ?

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What coefficient would the O_2O2O_2 have after balancing C_4H_8 + O_2 -> CO_2 + H_2OC4H8+O2→CO2+H2OC_4H_8 + O_2 -> CO_2 + H_2O?

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What coefficient would the $O_{2}$ $O_2$ have after balancing $C_{4} H_{8} + O_{2} \to C O_{2} + H_{2} O$ $C_4H_8 + O_2 -> CO_2 + H_2O$ ?