What could the $^{n} Pr$ $""^(n)"Pr"$ mean in $^{n} {PrNH}_{2}$ $""^(n)"PrNH"_2$ ?

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What could the $^{n} Pr$ $""^(n)"Pr"$ mean in $^{n} {PrNH}_{2}$ $""^(n)"PrNH"_2$ ?

Is it "normal propyl", like in $n$ $n$ -pentane, or something else? $Pr$ $"Pr"$ as an atom is praseodymium, but is it possible that $^{n} Pr$ $""^(n)"Pr"$ is normal-propyl?

I've seen $^{i} Pr$ $""^(i)"Pr"$ indicate isopropyl before.

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Answer 1 · 2017-12-02T17:59:59

It is $n-propyl$ $"n-propyl"$ , where $n$ $n$ is short for $normal$ $"normal"$ as you suspected....three carbon atoms in a straight chain...

Explanation:

And thus $n-propyl$ $"n-propyl"$ specifies the STRAIGHT CHAIN.... $H_{3} C - C H_{2} C H_{2} X$ $H_3C-CH_2CH_2X$ , and isopropyl specifies the branched chain, $P r^{i} \equiv - C H {(C H_{3})}_{2}$ $Pr^(i)-=-CH(CH_3)_2$ .

As for $praesodymium$ $"praesodymium"$ , I doubt any organic chemist could even find a lanthanide.....

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What could the $^{n} Pr$ $""^(n)"Pr"$ mean in $^{n} {PrNH}_{2}$ $""^(n)"PrNH"_2$ ?

Is it "normal propyl", like in $n$ $n$ -pentane, or something else? $Pr$ $"Pr"$ as an atom is praseodymium, but is it possible that $^{n} Pr$ $""^(n)"Pr"$ is normal-propyl?

I've seen $^{i} Pr$ $""^(i)"Pr"$ indicate isopropyl before.

1 Answer

Explanation:

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What could the nPr""^(n)"Pr" mean in nPrNH2""^(n)"PrNH"_2?

Is it "normal propyl", like in nn-pentane, or something else? Pr"Pr" as an atom is praseodymium, but is it possible that nPr""^(n)"Pr" is normal-propyl? I've seen iPr""^(i)"Pr" indicate isopropyl before.

1 Answer

Explanation:

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Impact of this question

What could the $^{n} Pr$ $""^(n)"Pr"$ mean in $^{n} {PrNH}_{2}$ $""^(n)"PrNH"_2$ ?

Is it "normal propyl", like in $n$ $n$ -pentane, or something else? $Pr$ $"Pr"$ as an atom is praseodymium, but is it possible that $^{n} Pr$ $""^(n)"Pr"$ is normal-propyl?

I've seen $^{i} Pr$ $""^(i)"Pr"$ indicate isopropyl before.