What does $cos (arctan (1)) + 3 csc (a r c csc (2))$ $cos(arctan(1))+3csc(arc csc(2))$ equal?

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What does $cos (arctan (1)) + 3 csc (a r c csc (2))$ $cos(arctan(1))+3csc(arc csc(2))$ equal?

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Answer 1 · 2016-03-25T04:39:59

$\frac{1}{\sqrt{2}} + 6$ $1/sqrt2+6$

Explanation:

As tan $(\frac{π}{4}) = 1$ $(pi/4)=1$ , arctan (1) = $\frac{π}{4}$ $pi/4$ and csc(arccsc(a)) =a.
So, the expression = cos $\frac{π}{4}$ $pi/4$ + 3X2 = $\frac{1}{\sqrt{2}}$ $1/sqrt2$ + 6.

Also, arctan(1) = arc cos $(\frac{1}{\sqrt{2}})$ $(1/sqrt2)$ .
cos $a r c cos (\frac{1}{\sqrt{2}}) = \frac{1}{\sqrt{2}}$ $arc cos (1/sqrt2)=1/sqrt2$ ..

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What does $cos (arctan (1)) + 3 csc (a r c csc (2))$ $cos(arctan(1))+3csc(arc csc(2))$ equal?

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What does cos(arctan(1))+3csc(arccsc(2))cos(arctan(1))+3csc(arc csc(2)) equal?

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What does $cos (arctan (1)) + 3 csc (a r c csc (2))$ $cos(arctan(1))+3csc(arc csc(2))$ equal?