What does $cos (arctan (\frac{π}{4}))$ $cos(arctan(pi/4))$ equal?

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What does $cos (arctan (\frac{π}{4}))$ $cos(arctan(pi/4))$ equal?

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Answer 1 · 2016-03-06T05:51:36

$= \frac{1}{\sqrt{1 + {(\frac{π}{4})}^{2}}}$ $=1/sqrt(1+(pi/4)^2$

Explanation:

$cos (arctan (\frac{π}{4}))$ $cos(arctan(pi/4))$
$= \frac{1}{sec (arctan (\frac{π}{4}))}$ $=1/sec(arctan(pi/4))$
$= \frac{1}{\sqrt{1 + {tan}^{2} (arctan (\frac{π}{4}))}}$ $=1/sqrt(1+tan^2(arctan(pi/4))$
$= \frac{1}{\sqrt{1 + ({tan (arctan (\frac{π}{4}))}^{2}}}$ $=1/sqrt(1+(tan(arctan(pi/4))^2$
$= \frac{1}{\sqrt{1 + {(\frac{π}{4})}^{2}}}$ $=1/sqrt(1+(pi/4)^2$

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What does $cos (arctan (\frac{π}{4}))$ $cos(arctan(pi/4))$ equal?

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