What does $sin (arccos (4)) - cot (a r c csc (5))$ $sin(arccos(4))-cot(arc csc(5))$ equal?

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What does $sin (arccos (4)) - cot (a r c csc (5))$ $sin(arccos(4))-cot(arc csc(5))$ equal?

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Answer 1 · 2016-03-13T09:23:24

$sin (arccos 4) - cot (a r c csc 5)$ $sin(arccos4)-cot(arc csc5)$ oes not exist.

Explanation:

ad the range of $cos θ$ $costheta$ is $[- 1, 1]$ $[-1,1]$ i.e. $cos θ$ $costheta$ can take values only between $- 1$ $-1$ and $1$ $1$ including $- 1$ $-1$ and $1$ $1$ ,

$sin (arccos (4))$ $sin(arccos(4))$ does not exist.

Hence $sin (arccos 4) - cot (a r c csc 5)$ $sin(arccos4)-cot(arc csc5)$ oes not exist.

However, $arccsc(5)=arcsin(1/5)=11.537^o$ or $168.463^o$ .

Hence $cot(arc csc5)=cot11.537^o=4.899$ or

$cot(arc csc5)=cot168.463^o=-4.899$

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What does $sin (arccos (4)) - cot (a r c csc (5))$ $sin(arccos(4))-cot(arc csc(5))$ equal?

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Explanation:

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