What does $sin(arccot(5))-sin(arcsec(2))$ equal?

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Answer 1 · 2016-07-20T04:22:28

$1/sqrt 26-sqrt 3/2=-0.66991$ , nearly.

Use $sin (arc sin( c)) = c$ .

Confining to principal values of inverse functions thai are in the 1st

quadrant,

$arc cot(5)=arc tan(1/5)=arc sin (1/sqrt 26$ and

$arc sec(2)=arc cos(1/2)=arc sin (sqrt 3/2)$

Now, the given expression is

$sinarc sin (1/sqrt 26)-sin arc sin (sqrt 3/2)$

$=1/sqrt 26- sqrt 3/2=0.6991$ , nearly.

What does sin(arccot(5))-sin(arcsec(2))sin(arccot(5))-sin(arcsec(2)) equal?