What does $tan (a r c sec (2)) - 2 cos (a r c cot (3))$ $tan(arcsec(2))-2cos(arc cot(3))$ equal?

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What does $tan (a r c sec (2)) - 2 cos (a r c cot (3))$ $tan(arcsec(2))-2cos(arc cot(3))$ equal?

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Answer 1 · 2016-04-20T05:43:45

$\pm \sqrt{3} \pm (\frac{3}{5}) \sqrt{10}$ $+-sqrt 3+-(3/5)sqrt 10$ = 3.629, - 1.653, 0.1653 and -3.629, nearly.

Explanation:

If sec is positive, tan could be positive or negative.
Let $a = a r c sec 2 . sec a = 2 and tan a = \pm \sqrt{3}$ $a=arc sec 2. sec a=2 and tan a=+-sqrt 3$ .

So, the first term $tan (a r c sec 2) = \pm \sqrt{3}$ $tan(arc sec 2)=+-sqrt3$

If cot is positive, cos could be positive or negative.
Let $b = a r c cot 3 . cot b = 3 and cos b = \pm \frac{3}{\sqrt{10}}$ $b=arc cot 3. cot b=3 and cos b=+-3/sqrt 10$ .

So, the second term $- 2 cos (a r c cot 3) = - 2 cos b = \pm \frac{6}{\sqrt{10}}$ $-2 cos(arc cot 3)=-2 cos b=+-6/sqrt 10$ .

Remembering that the sign choice from $\pm$ $+-$ is independent for each term,
the sum is $\pm \sqrt{3} \pm \frac{6}{\sqrt{10}} = \pm 3.629, \pm 1.653$ $+-sqrt 3+-6/sqrt 10=+-3.629, +-1.653$ , nearly. . .

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What does $tan (a r c sec (2)) - 2 cos (a r c cot (3))$ $tan(arcsec(2))-2cos(arc cot(3))$ equal?

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Explanation:

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