What does $tan (a r c sec (6) - 5 cos (arcsin (3))$ $tan(arcsec(6)-5cos(arcsin(3))$ equal?

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What does $tan (a r c sec (6) - 5 cos (arcsin (3))$ $tan(arcsec(6)-5cos(arcsin(3))$ equal?

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Answer 1 · 2016-03-11T17:02:00

arcsin(3) is the angle, with sin (the angle) = 3.
For every x, $- 1 \leq sin (x) \leq + 1$ $-1 <= sin (x) <=+1$ .
3 is out of bounds for the sine function..

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What does $tan (a r c sec (6) - 5 cos (arcsin (3))$ $tan(arcsec(6)-5cos(arcsin(3))$ equal?

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What does tan(arcsec(6)−5cos(arcsin(3))tan(arcsec(6)-5cos(arcsin(3)) equal?

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What does $tan (a r c sec (6) - 5 cos (arcsin (3))$ $tan(arcsec(6)-5cos(arcsin(3))$ equal?