What does the expression $6 [(z^{2} + 3 (0 + 2)]$ $6[(z^2 +3 (0+2)]$ equal with z is -4?

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Answer 1 · 2015-04-22T18:56:58

$6 [(z^{2} + 3 (0 + 2)]$ $6[(z^2+3(0+2)]$ when $z = - 4$ $z=-4$

$= 6 [({(- 4)}^{2} + 3 (0 + 2)]$ $= 6[((-4)^2+3(0+2)]$

$= 6 [({(- 4)}^{2} + 3 \cdot 2)]$ $= 6[((-4)^2+3*2)]$

$= 6 [(16 + 3 \cdot 2]$ $= 6[(16+3*2]$

$= 6 [16 + 6]$ $= 6[16+6]$

$= 6 [22]$ $= 6[22]$

$= 132$ $= 132$

What does the expression 6[(z2+3(0+2)]6[(z^2 +3 (0+2)] equal with z is -4?