What does the expression #6[(z^2 +3 (0+2)]# equal with z is -4? Algebra Expressions, Equations, and Functions PEMDAS 1 Answer Alan P. Apr 22, 2015 #6[(z^2+3(0+2)]# when #z=-4# #= 6[((-4)^2+3(0+2)]# #= 6[((-4)^2+3*2)]# #= 6[(16+3*2]# #= 6[16+6]# #= 6[22]# #= 132# Answer link Related questions What is PEMDAS? How do you use PEMDAS? How do you use order of operations to simplify #3(7-2)-8#? What are common mistakes students make with PEMDAS? How do you evaluate the expression #5[8+(3-1)]-2#? How do you simplify the expression #4(30-(3+1)^2)#? How do you evaluate the expression #x^4+x# if x=2? Is it okay to add first before subtracting in #4-6+3#? How do you simplify #(-3)^2+12*5#? How do you simplify #(4-2)^3-4*8+21div3#? See all questions in PEMDAS Impact of this question 1827 views around the world You can reuse this answer Creative Commons License