What happens in a dynamic equilibrium exits in a reaction?

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What happens in a dynamic equilibrium exits in a reaction?

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Answer 1 · 2017-07-24T15:50:03

$Option (b) is the answer I would choose.......$ $"Option (b) is the answer I would choose......."$

Explanation:

Consider the hypothetical reaction:

$A + B ⇌ C + D$ $A+BrightleftharpoonsC+D$

Now there is a forward rate.......

$Rate forward = k_{f} [A] [B]$ $"Rate forward"=k_f[A][B]$

And there is a reverse rate.......

$Rate backwards = k_{r} [C] [D]$ $"Rate backwards"=k_r[C][D]$ .

The condition of chemical equilibrium does not specify the cessation of chemical change; it does specify equality of FORWARD and REVERSE rates.

$Rate forward = Rate backward$ $"Rate forward"="Rate backward"$ , and so.........

$k_{f} [A] [B] \equiv k_{r} [C] [D]$ $k_f[A][B]-=k_r[C][D]$ .......and so......

$\frac{k_{f}}{k_{r}} = \frac{[C] [D]}{[A] [B]}$ $k_f/k_r=([C][D])/([A][B])$

We commonly call the $\frac{k_{f}}{k_{r}}$ $k_f/k_r$ quotient as $K_{eq}$ $K_"eq"$ , the $thermodynamic equilibrium constant$ $"thermodynamic equilibrium constant"$ , which is usually independent of temperature.

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What happens in a dynamic equilibrium exits in a reaction?

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