What happens to an oxidizing agent during a redox reactions?

1 Answer
Jun 16, 2017

The oxidizing reagent is FORMALLY reduced.......

Explanation:

Redox reactions are conceived to occur on the basis of CONCEPTUAL electron transfer, and typically we write out separate redox processes.........

For oxidation of methane we could write...........

IV CH4(g)+2H2O+IVCO2(g)+4H++8e (i)

And for every oxidation, there must be a corresponding reduction; here of dioxygen gas to water..........

0O2(g)+4H++4e2H2IIO (ii)

And this is the FORMAL reduction reaction. Oxygen decreases in oxidation number, and it has FORMALLY GAINED electrons.....

0O2+4e2IIO2

And add the two half equation together.......so that we eliminate the electrons: (i)+2×(ii)

0CH4(g)+20O2(g)+IVCO2(g)+2H2O(g)

Of course, I am making a meal of it here; I could simply follow the usual rigmarole and (i) balance the carbons, (ii) balance the hydrogens as water, and (iii) balance the oxygens.