What happens to the total resistance when a fourth resistor is connected in a series with three resistors?

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Answer 1 · 2015-03-16T04:42:06

Well we know that when a resistor is connected in series

$R_n =R_1 + R_2 + R_3....$

So i am taking that the forth resistor has the same resistance as the first 3

$i.e. R_1=R_2=R_3=R_4$

Okay so lets say the increase $% =$ Increase $/$ original $* 100$

$= R_4/ (R_1 + R_2 + R_3) *1 00$

given that

$R_1=R_2=R_3=R_4$

We can rewrite as
$= R_4/ (3R_4) *100$
$=1/3 *100$

$therefore$ Resistance increases by $30.333..... %$