Question

What is -`"2pi"/5` radians in degrees?

Answer 1

`((-2pi)/5)^R=-72^circ`

Explanation:

We know that,

`color(red)(pi^R=180^circ`

So,

`((-2pi)/5)^R=(180/cancelpixx(-2cancelpi)/5)^circ`

`=>((-2pi)/5)^R=(-(cancel180^36xx2)/cancel5)^circ`

`=>((-2pi)/5)^R=-72^circ`