What is 2xy differentiated implicitly?

2 Answers
Sep 2, 2015

y'=(2y)/(1-2x)

Explanation:

The question does not specify with respect to what so I'll assume y is a function of x.

Use the product rule:

y' = d((u.v))/dx=v.du/dx+u.dv/dx

So:

y'=2x.y'+y2.dx/dx

y'=2x.y'+2y

y'=(2y)/(1-2x)

Jul 20, 2018

The answer is =-y/x

Explanation:

The function is

f(x,y)=2xy

The partial derivatives are

(delf)/(delx)=2y

(delf)/(dely)=2x

Therefore,

dy/dx=-((delf)/(delx))/((delf)/(dely))=-(2y)/(2x)=-y/x