What is $(3 w^{2} + 2 w) + (5 w^{2} - 7 w)$ $(3w^2+2w) + (5w^2-7w)$ ?

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Answer 1 · 2018-06-06T09:39:57

Just add them

Arrange the equation:

$3 w^{2} + 2 w + 5 w^{2} - 7 w$ $3w^2 + 2w + 5w^2 - 7w$ after getting rid of parantheses

$= (3 + 5) w^{2} + (2 - 7) w$ $=(3+5)w^2 + (2-7)w$

$= 8 w^{2} - 5 w$ $=8w^2 -5w$

$= w (8 w - 5)$ $=w(8w-5)$

Your answer is

$w (8 w - 5)$ $w(8w-5)$

Answer 2 · 2018-06-12T02:22:54

$\Rightarrow w (8 w - 5)$ $color(green)(=> w (8w - 5)$

$(3 w^{2} + 2 w) + (5 w^{2} - 7 w)$ $(3w^2 + 2w) + (5w^2 - 7w)$

$\Rightarrow 3 w^{2} + 2 w + 5 w^{2} - 7 w, after removing the braces$ $=> 3w^2 + 2w + 5w^2 - 7w, "after removing the braces"$

$\Rightarrow 3 w^{2} + 5 w^{2} + 2 w - 7 w, bringing like terms together$ $=> 3w^2 + 5w^2 + 2w - 7w, " bringing like terms together"$

$\Rightarrow 8 w^{2} - 5 w, Adding / Subtracting$ $=> 8w^2 - 5w, " Adding / Subtracting"$

$\Rightarrow w \cdot (8 w - 5), Taking common term out$ $=> w * (8w - 5), " Taking common term out"$

What is (3w^2+2w) + (5w^2-7w)(3w2+2w)+(5w2−7w)(3w^2+2w) + (5w^2-7w)?