What is $(4^2-8)2^3-85-:10$ ?

Question

2222 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-07T04:51:23

$[(16-8)xx8]-40/10= 64-4=60$

It's actually extremely simple if you know the order of operations.
PEMDAS!

It also goes left to right! So beginning with the parentheses, we focus on what is in the parentheses

$( 4^2 -8)$

meaning $16$ , which is the square of $4$ , subtracted by $8$ . which turns in to $8$ .

$( 4^2 -8) = 16 - 8 = 8$

After the paratheses, you multiply by $8$ the cube of $2$ , which is then subtracted by $4$ .

$8 xx 2^3 = 8 xx 8 = 64$

Since, if you follow PEMDAS and multiply then divide from left to right, it's $40/10$ , which is $4$ . So the answer, in the end, is

$64 - 40/10 = 64 - 4 = 60$

What is (4^2-8)*2^3-8*5-:10(4^2-8)*2^3-8*5-:10?