What is $(- 6+ | - 3| ) \cdot ( 4- 3\cdot 2) \div ( | - 2| )$ ?

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Answer 1 · 2017-06-21T13:40:37

3

The absolute value of $-3$ is $3$ .

The absolute value of $-2$ is $2$ .

Let's rewrite the equation

$(-6+3)*(4-3*2)div(2)$

Let's solve the LHS bracket.

$-6+3=-3$

$-3*(4-3*2)div(2)$

Now, the middle bracket.

$4-3*2$ ←　 You have to multiply first
$4-6$
$-2$

$-3*-2div(2)$
$6div2$
$3$

What is (- 6+ | - 3| ) \cdot ( 4- 3\cdot 2) \div ( | - 2| )(- 6+ | - 3| ) \cdot ( 4- 3\cdot 2) \div ( | - 2| )?