Question

What is `6/(5+i)` written in standard form?

Answer 1

`6/(5 + I).`

Multiply both numerator and denominator by (5 - i)#

`[6.(5 - i)]/[(5 + i)(5 - i)] = [6(5 - i)]/(25 - i^2) = [6(5 - i)]/26 = [3(5 - i)]/13`

Reminder: `i^2 = -1`