What is #8 1/4 div 3#?

3 Answers

#2 3/4 "or " 11/4#

Explanation:

So we start off with with this:

#(8(1/4))/3#

This means that we have 8 wholes and a fourth. To get this in fraction form:
1.Take the number in front of the fraction times the denominator

#8*4=32# quarters

2.Now plus the numerator to get the total number of quarters

#32+1=33# quarters

So now we have: #(33/4)/3#

We can extend the 3 to #3/1#

It's the exactly the same thing just different numbers.

Now we have:

#(33/4)/(3/1)#

Now we divide them by flipping the bottom one and then multiplying so we get:

#33/4xx1/3=33/12#

Now we can simplify by dividing by three in the numerator and in the denominator so we get

#11/4 = 2 3/4#

Hope this helps =).

Apr 18, 2018

#2 3/4#

A lot of detail given so you can see the way everything works. In reality you would use a lot less lines.

Explanation:

Consider the #-:3# this has the same outcome as #xx1/3#
So now we have:

#color(blue)(8 1/4xx1/3)#

Consider the #8 1/4#. Write as #8+1/4#

Multiply by 1 and you do not change the value. However, 1 comes in many forms

#color(green)( [8 color(red)(xx1)]+1/4 color(white)("dddd")-> color(white)("dddd")[8color(red)(xx4/4)]+1/4#

#color(green)(color(white)("ddddddddddddd")-> color(white)("ddd.dd")[32/4]color(white)("d")+1/4= 33/4 #

#color(green)(8 1/4 = 33/4)#

Putting it all back together we have:

#color(blue)(33/4xx1/3)#

#color(green)((33xx1)/(4xx3)color(white)("dd") =color(white)("dd") (33xx1)/(3xx4)color(white)("dd") =color(white)("dd") cancel(33)^11/cancel(3)^1xx1/4color(white)("d")=color(white)("d")11/4#

#color(blue)(11/4color(white)("dd") ->color(white)("dd")2 3/4 larr" Same format as in the question")#

Apr 19, 2018

#11/4 =2 3/4#

Explanation:

To divide with fractions:

  • Make improper fractions.
  • multiply by the reciprocal
  • cancel where possible
  • multiply straight across

#8 1/4 div 3#

#= 33/4 xx1/3#

#= cancel33^11/4 xx1/cancel3#

#=11/4#

#= 2 3/4#

Answer in the same format as the question, so give the answer as a mixed number,