First of all, using the definitions #a = (dv)/(dt)# and #F = ma#, the definition of impulse is:
#I = intFdt = int madt = m int(dv)/cancel(dt)cancel(dt)#
#I = m intdv#
#I = mDeltav#
...whereas #p = mv#
Thus, an impulse causes an object to change velocity as a result of an impact. Or, it can be said that it is summation of the infinite instances of instantaneous force applied over a small amount of time.
A nice example is right when a golf club hits a golf ball. Let's say there was a constant impulse for #0.05 s# on a golf ball started at rest. If the golf ball is #45 g# and its velocity after it leaves contact with the golf club is #50 m/s#, what was the impulse?
#I = mDeltav#
#I = (0.045 kg)(50 m/s - 0 m/s) = 2.25 kg*m/s#
The average force applied onto the golf ball in these #0.05# seconds would be what?
#F_(avg) = 1/Nsum_(i=1)^NF_i = (FDeltat)/(Deltat) = I/(Deltat) = (2.25 N*s) / (0.05 s) = 45 N#
And I'll leave this one for you:
If the golf ball leaves the tee at a #45^o# from the horizontal, how long does it take for it to cross the spot that lines up horizontally with its initial position?