What is f(x) = int 1/(x^2+3) f(x)=∫1x2+3 if f(2)=1 f(2)=1?

1 Answer
Bdub
Mar 16, 2016

f(x)=int1/(x^2+3) = 1/sqrt3 tan^-1(x/sqrt3) +Cf(x)=∫1x2+3=1√3tan−1(x√3)+C
f(2)=1/sqrt3 tan^-1(2/sqrt3) +C=1f(2)=1√3tan−1(2√3)+C=1
C=1-(1/sqrt3 tan^-1(2/sqrt3))~~0.505C=1−(1√3tan−1(2√3))≈0.505
f(x)=int1/(x^2+3) = 1/sqrt3 tan^-1(x/sqrt3) +0.505f(x)=∫1x2+3=1√3tan−1(x√3)+0.505

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