Question

What is Hubble's constant in light years?

Answer 1

Hubble constant `H_o = 71` km /sec/mega parsec = `4.5 X 10^(-12)` light year/sec/mega parsec.

Explanation:

Hubble constant `H_o = 71` km /sec/mega parsec

`71 km`

`= 71/499792=1.42 X 10^(-4)` light seconds

`=1.42 X 10^(-4)/(365.256 X 24 X 60 X 60)`

`= 4.5 X 10^(-12)` light years.

S0, `H_o = 4.5X 10^(-12)` light years/sec/mega parsec..
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