What is lim_(xrarroo) ( 1 + ( r/x ) ) ^ x, where r is any real number?

1 Answer
Oct 27, 2015

lim_(xrarroo)(1+r/x)^x = e^r

Explanation:

(1+r/x)^x = ((1+r/x)^(x/r))^r

Let u = rx.so this becomes ((1+1/u)^u)^r

Note that as xrarroo, we also have u rarroo

So,

lim_(xrarroo(1+r/x)^x = lim_(urarroo)((1+1/u)^u)^r

= (lim_(urarroo)(1+1/u)^u)^r

= e^r