What is $lim_(xrarroo) ((6x) / e^x)$ ?

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Answer 1 · 2018-04-15T16:47:49

The limit equals $0$

Since we're of the form $oo/oo$ , we may apply l'hospitals.

$L = lim_(x->oo) 6/e^x$

$L = lim_(x->oo) 6e^(-x)$

Since $e^-x$ converges to $0$ as $x -> oo$ , we can say

$L = 0$

Hopefully this helps!

What is lim_(xrarroo) ((6x) / e^x) lim_(xrarroo) ((6x) / e^x) ?