Question

What is `P(x)` for `n= 6,x = 3, q=0.7`?

Answer 1

`P(3)=0.18522`.

Explanation:

`P(x)=""_nC_xp^xq^(n-x), x=0,1,2,3,...,n; and, p+q=1.`

We have, `n=6, x=3, and, q=0.7 rArr p=1-q=0.3`

`:. P(3)=""_6C_3(0.3)^3(0.7)^(6-3)`

`=(20)(0.3)^3(0.7)^3`

`=20(0.21)^3`

`:. P(3)=20(0.009261)=0.18522`.