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What is pH when $[H^+] = 8.43 * 10^-4$ $M$ ?

1 Answer

Nov 24, 2016

$pH=3.07$

Explanation:

$pH=-log_10[H^+]$ , equivalently $pH=-log_10[H_3O^+]$ .

$-log_10(8.43xx10^-4)=-(-3.07)=3.07$

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