What is sec(arcsin (4/5))sec(arcsin(45))?

1 Answer
Nghi N.
Aug 16, 2015

Find sec (arcsin (4/5))sec(arcsin(45))

Ans +- 1.67±1.67

Explanation:

Using calculator -->
sin x = 4/5 = 0.80sinx=45=0.80 --> arc x = 53.15x=53.15 deg and
arc x = 180 - 53.15 = 126.85x=180−53.15=126.85 deg
cos 53.15 = 0.60
sec (53.15) = 1/cos 53.15 = 1/0.60 = 1.67sec(53.15)=1cos53.15=10.60=1.67

cos 126.85 = -0.60
sec (126.85) = 1/cos = 1/-0.6 = -1.67
Ans: +- 1.67±1.67

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