What is #sqrt106# in simplified radical form?
1 Answer
Aug 9, 2017
Explanation:
Factoring
#106 = 2*53#
It has no square factors and hence there is no factor we can separate out and bring outside the radical.
We could write:
#sqrt(106) = sqrt(2*53) = sqrt(2)sqrt(53)#
but that is not (usually) considered simplified.