What is ${tan}^{- 1} (\frac{\sqrt{3}}{3})$ $tan^-1(sqrt3/3)$ ?

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Answer 1 · 2018-03-06T07:51:54

$θ = {(\frac{π}{6})}^{c}$ $color(green)(theta = (pi / 6 )^c$ or $= 30^{\circ}$ $color(green)( = 30^@$

Let $θ = {tan}^{- 1} (\frac{\sqrt{3}}{3})$ $theta = tan ^-1 (sqrt3/3)$

$tan θ = \frac{\sqrt{3}}{3}$ $tan theta = sqrt3 / 3$

$tan theta = cancel sqrt 3 / ( sqrt 3 * cancel sqrt3$

$tan theta = 1 / sqrt 3$

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From the above table,

$tan theta = 1 / sqrt 3$ or $theta = =( pi / 6)^c$ or $30^@$

What is tan^-1(sqrt3/3)tan−1(√33)tan^-1(sqrt3/3)?