What is the 32nd term of the arithmetic sequence where a1 = 4 and a6 = 24?

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What is the 32nd term of the arithmetic sequence where a1 = 4 and a6 = 24?

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Answer 1 · 2016-01-20T22:24:51

32nd term $a_{32} = 128$ $a_32 = 128$

Explanation:

If $a_{1}$ $a_1$ is first term, $d$ $d$ is the common difference, and $a_{n}$ $a_n$ is the $n t h$ $nth$ term of an arithmetic sequence, then relationship between these is

$a_n = a_1 + (n – 1)d$

To find $d$ , plug-in the given values
$a_6 = a_1 + (6 – 1)d$
$24 = 4 + (6 – 1)d$
Solving for $d$ we obtain
$5d=20$
or $d=4$

To find 32nd term, plug-in appropriate values
$a_32 = 4 + (32 – 1)4$
$a_32 = 128$

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What is the 32nd term of the arithmetic sequence where a1 = 4 and a6 = 24?

1 Answer

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