Question

What is the amplitude, period and the phase shift of `y=12 cos 3(x-theta/2)`?

Answer 1

`12, {2\pi}/3, -{3\theta}/2`

Explanation:

The given trigonometric function

`y=12\cos3(x-\theta/2)`

`y=12\cos(3x-{3\theta}/2)`

Amplitude `=12`

Period `={2\pi}/3`

Phase shift `=-{3\theta}/2`