What is the angle between <5,9,-2 > <5,9,−2> and < 6,-2,7><6,−2,7>?

1 Answer
Binayaka C.
Nov 26, 2016

Angle between the vectors is 91.16^091.160

Explanation:

Let vecu =<5,9, -2> and vecv =<6,-2,7> ; theta→u=<5,9,−2>and→v=<6,−2,7>;θ be the angle

between them ; then we know cos theta= (vecu*vecv)/(||vecu||*||vecv||)=((5*6)+(9* -2)+(-2*7))/(sqrt(5^2+9^2+ (-2)^2)* (sqrt(6^2+(-2)^2+7^2))cosθ=→u⋅→v∣∣∣∣→u∣∣∣∣⋅∣∣∣∣→v∣∣∣∣=(5⋅6)+(9⋅−2)+(−2⋅7)√52+92+(−2)2⋅(√62+(−2)2+72) = -2/(sqrt110*sqrt89)==-0.02021336:. theta=cos^-1(-0.02021336)=91.16^0[Ans]

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