What is the angle between $< 6, 8, 1 >$ $<6,8,1 >$ and $< 4, 7, 3 >$ $< 4, 7, 3 >$ ?

Question

2007 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-02-16T17:02:36

arccos ((cross product)/(product of the lengths of the vectors))
= arccos (83/( $\sqrt{101} \sqrt{}$ $sqrt101sqrt$ 74))
= 16.25 deg, nearly.

Here, the cross product = 6 X 4 = 8 x 7 +1 X 3 = 83. The lengths of the vectors are $\sqrt{}$ $sqrt$ 101 and $\sqrt{}$ $sqrt$ 74.

What is the angle between <6,8,1><6,8,1 > and <4,7,3>< 4, 7, 3 >?