What is the angle between <7,-2,8><7,−2,8> and < 7,3,-8><7,3,−8>?

1 Answer
Binayaka C.
Nov 30, 2016

Angle theta=100.12^0θ=100.120

Explanation:

Let vecu =<7,-2, 8> and vecv =<7,3,-8> ; theta→u=<7,−2,8>and→v=<7,3,−8>;θ be the angle between them ; then we know cos theta= (vecu*vecv)/(||vecu||*||vecv||)=((7.7)+(-2*3)+(8*-8))/(sqrt(7^2+(-2)^2+8^2)* (sqrt(7^2+3^2+(-8)^2))cosθ=→u⋅→v∣∣∣∣→u∣∣∣∣⋅∣∣∣∣→v∣∣∣∣=(7.7)+(−2⋅3)+(8⋅−8)√72+(−2)2+82⋅(√72+32+(−8)2) = (-21)/(sqrt117*sqrt122)=-0.1757:. theta=cos^-1(0.1757)=100.12^0[Ans]

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