What is the angle between <7,9,2> and <2,3,5>?

1 Answer
Dec 14, 2016

The angle is =87.7º

Explanation:

The angle between 2 vectors is given by the dot product definition

a.b=abcosθ

The dot product is

7,9,2.2,3,5=((72)+(93)+(25))

=14+2710=3

The modulus of a=7,9,2=63+81+4=144=12

The modulus of b=2,3,5=4+9+25=38

Therefore,

cosθ=a.bab=31238=0.04

θ=87.7º