What is the angle between $< - 9, 2, - 4 >$ $<-9 , 2 , -4 >$ and $< 5, 2, 0 >$ $< 5 , 2 , 0 >$ ?

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What is the angle between $< - 9, 2, - 4 >$ $<-9 , 2 , -4 >$ and $< 5, 2, 0 >$ $< 5 , 2 , 0 >$ ?

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Answer 1 · 2016-02-16T12:06:23

139.25 deg.

Explanation:

Let the vectors be called AC and AB.
Then the vector BC = AB - AC = <14, 0, 4>.
The sides a, b and c of the $△$ $triangle$ ABC are 2 $\sqrt{}$ $sqrt$ 53, $\sqrt{}$ $sqrt$ 101 and $\sqrt{}$ $sqrt$ 29.
The angle at A is arccos (( b.b + c.c - a.a ) / (2bc)).= arccos ( - 0..7576) =139.25 deg.

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What is the angle between $< - 9, 2, - 4 >$ $<-9 , 2 , -4 >$ and $< 5, 2, 0 >$ $< 5 , 2 , 0 >$ ?

1 Answer

Explanation:

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Science

Math

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What is the angle between <−9,2,−4><-9 , 2 , -4 > and <5,2,0> < 5 , 2 , 0 > ?

1 Answer

Explanation:

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Impact of this question

What is the angle between $< - 9, 2, - 4 >$ $<-9 , 2 , -4 >$ and $< 5, 2, 0 >$ $< 5 , 2 , 0 >$ ?