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What is the angle between $<-9,4,0>$ and $<-8,2,-7 >$ ?

1 Answer

Dec 11, 2016

$theta= cos^-1 0.7509= 41.33^o$

Explanation:

If the angle between the two vectors is $theta$ , then $cos (theta)=( (-9)(-8) +(4)(2) +0(-7))/(sqrt((-9)^2 +4^2 +0) sqrt((-8)^2 + 2^2 +(-7)^2)$

= $80/(sqrt97 sqrt117$ =0.7509

$theta= cos^-1 0.7509= 41.33^o$

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