What is the angle between $< 9, - 8, 1 >$ $<9,-8,1 >$ and $< 4, - 7, 1 >$ $< 4,-7,1 >$ ?

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What is the angle between $< 9, - 8, 1 >$ $<9,-8,1 >$ and $< 4, - 7, 1 >$ $< 4,-7,1 >$ ?

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Answer 1 · 2018-04-18T17:48:11

$< 9, - 8, 1 > \cdot < 4, - 7, 1 \geq | < 9, - 8, 1 > | ∣ < 4, - 7, 1 > cos θ$ $<9,-8,1>*<4,-7,1>=|<9,-8,1>||<4,-7,1>cos theta$
$(36 + 56 + 1) = (\sqrt{9^{2} + 8^{2} + 1^{2}}) (\sqrt{4^{2} + 7^{2} + 1^{2}}) cos θ$ $(36+56+1)=(sqrt(9^2+8^2+1^2))(sqrt(4^2+7^2+1^2))cos theta$
$93 = 98.1631 cos θ$ $93=98.1631costheta$
$cos θ = 0.9474$ $cos theta=0.9474$
$θ = {cos}^{- 1} 0.9474$ $theta=cos^-1 0.9474$
$θ = 0.325784303 r a d$ $theta=0.325784303 rad$

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What is the angle between $< 9, - 8, 1 >$ $<9,-8,1 >$ and $< 4, - 7, 1 >$ $< 4,-7,1 >$ ?

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What is the angle between <9,−8,1><9,-8,1 > and <4,−7,1>< 4,-7,1 >?

1 Answer

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What is the angle between $< 9, - 8, 1 >$ $<9,-8,1 >$ and $< 4, - 7, 1 >$ $< 4,-7,1 >$ ?