What is the antiderivative of 3e^x3ex?

1 Answer
Jan 27, 2016

3e^x+C3ex+C

Explanation:

You should already know that the derivative of e^xex is just e^xex. Also, when differentiating, multiplicative constants remain and are not altered.

Since the two components of this function are a multiplicative constant 33 and e^xex, we can say that d/dx(3e^x)=3e^xddx(3ex)=3ex.

Thus, the antiderivative of the function is just 3e^x+C3ex+C.

The CC, or the constant of integration, is added because constants have no bearing when finding a derivative.

More formally, we could use substitution.

{(u=x),((du)/dx=1=>du=dx):}

We want to find

int3e^xdx=3inte^xdx

Simplify with u substitution:

=3inte^udu

Use the rule that inte^udu=e^u+C

=3e^u+C=3e^x+C