What is the antiderivative of e^-x?
1 Answer
Jan 12, 2017
int \ e^(-x) \ dx = -e^(-x) + C
Explanation:
Using
d/dx e^(ax) = ae^(ax) => int \ e^(ax) \ dx= 1/ae^(ax)
Then,
int \ e^(-x) \ dx= 1/(-1)e^(-x) + C
" "= -e^(-x) + C