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What is the antiderivative of ${(x - 3)}^{2}$ $(x-3)^2$ ?

1 Answer

May 23, 2018

It is $\frac{{(x - 3)}^{3}}{3} + C$ $(x-3)^3/3+C$

Explanation:

Use that $\int x^{n} d x = \frac{x^{n + 1}}{n + 1} + C$ $int x^ndx=x^(n+1)/(n+1)+C$ if $n \neq - 1$ $n\ne -1$

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