What is the approximate distance between (3, 6, -7) and(-4, 1, 5)?

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1 Answer
Jim G.
May 22, 2018

√218≈14.76 to 2 dec. places

Explanation:

use the 3-d version of the distance formula

∙xd=√(x2−x1)2+(y2−y1)2+(z2−z1)2

let (x1,y1,z1)=(3,6,−7),(x2,y2,z2)=(−4,1,5)

d=√(−4−3)2+(1−6)2+(5+7)2

d=√(−7)2+(−5)2+122

d=√49+25+144=√218≈14.76

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