What is The area of a triangle whose vertices are j (-2,1), k (4,3) and l (-2,-5)?

1 Answer
Apr 23, 2018

1818.

Explanation:

Recall that, the Area Delta of DeltaABC with vertices

A(x_1,y_1), B(x_2,y_2) and C(x_3,y_3) is given by,

Delta=1/2|D|, where,

D=|(x_1,y_1,1),(x_2,y_2,1),(x_3,y_3,1)|,

In our case, D=|(-2,1,1),(4,3,1),(-2,-5,1)|,

=-2{3-(-5)}-1{4-(-2)}+1{-20-(-6)},

=-16-6-14,

=-36.

rArr Delta=18.