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What is the average or mean slope of the function $2x^3 - 6x^2 - 48x + 4$ on the interval [-4,9]?

1 Answer

Oct 5, 2015

The mean slope (aka the average rate of change) of $f$ on $[-4,9]$ is $(f(9)-f(4))/(9-(-4))$

Explanation:

For $f(x) = 2x^3 - 6x^2 - 48x + 4$ , we have
$f(-4) = -28$ $" "$ and $" "$ $f(9)=544$

So the mean slope is

$(f(9)-f(4))/(9-(-4)) = (544-(-28))/(9-(-4))$

$= 572/13 = 44$

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