Question

What is the axis of symmetry and vertex for the graph `f(x)=x^2 – 2x – 13`?

Answer 1

Vertex is at `(1,-14)` , the axis of symmetry is `x = 1`

Explanation:

`f(x) =x^2-2x-13 or f(x) =(x^2-2x+1) -1-13` or

`f(x)= (x-1)^2 -14` Comparing with vertex form of equation

`f(x) = a(x-h)^2+k ; (h,k)` being vertex we find here

`h=1,k=-14 :.` Vertex is at `(1,-14)` . The axis of symmetry

is `x=h or x = 1`

graph{x^2-2x-13 [-40, 40, -20, 20]} [Ans]